division

How to Divide two numbers in Java| 5 different ways

How to Divide two numbers in Java| 5 different ways

In this article, we will discuss the concept of How to Divide two numbers in Java| 5 different ways

In this post, we are going to learn how to write a program to 5 Ways to Division of Two Numbers (With Examples) in  Java programming language.

Divide two numbers

Division of two numbers in Java

here, I’ll give you separate short programs for each method so it’s easier to understand

Using simple division operator

The simplest and most common way to divide two numbers

Program 1

// Divide two nunbers using simple division operator

class DivideNum {
    public static void main(String[] args) {
        int num1=24;
        int num2=4;
        int result=num1/num2;
         System.out.println("Division using / operator ");
        System.out.println("Division is: "+result);
    }
}

When the above code is executed, it produces the following result

Division using / operator
Division is: 6

 

Using Scanner class

Division of two numbers Using Allows users to enter numbers at runtime.

Program 2

// Divide two nunbers using Scanner Class
import java.util.Scanner;
class DivideNum2 {
    public static void main(String[] args) {
        Scanner input=new Scanner(System.in);
        System.out.println("Enter first number ");
        double num1=input.nextDouble();
         System.out.println("Enter second number ");
        double num2=input.nextDouble();
        double result=num1/num2;
         System.out.println("Division using Scanner ");
        System.out.println("Division is: "+result);
    }
}

When the above code is executed, it produces the following result

Enter first number
33
Enter second number
11
Division using Scanner
Division is: 3.0

 

Using User defined method

Division is done inside a method for reusability.

Program 3

// Divide two nunbers using user defined-method
class DivideNum2 {
    public static double divide(double a, double b){
        if(b==0){
            System.out.println("Cannot divide by zero ");
            return 0;
        }
        return a/b;
        
    }
    public static void main(String[] args) {
        double result=divide(25,5);
         System.out.println("Division using user difined method ");
         System.out.println("Division is: "+result);
        
    }
}

When the above code is executed, it produces the following result

Division using user defined method
Division is: 5.0

 

Using loops (Repeated Subtraction method)

performs division without using the / operator – good for understanding logic

Program 4

// Divide two numbers using while loop

class DivideNumbers {
    public static void main(String[] args) {
        int dividend=30;
        int divisor=4;
        int quotient=0;
        while(dividend>= divisor){
         dividend-=divisor;
         quotient++;
        }
        System.out.println("Quotient using loop: "+quotient);
        System.out.println("Remainder: "+dividend);
    }
}

When the above code is executed, it produces the following result

Quotient using loop: 7
Remainder: 2

 

Using recursion

Program 5

// Divide two numbers using recursion
class DivideNum2 {
     // Method to divide two numbers
    public static int divide(int dividend, int divisor){
        if(divisor==0){
            
            throw new ArithmeticException("Cannot divide by zero ");
        }
        if(dividend<divisor){
        return 0;
        }
        return 1+divide(dividend - divisor,divisor);
    }
    public static void main(String[] args) {
        
         System.out.println("Division using user difined method ");

        // Calling the divide method
        double result = divide(20,4);

        // Displaying the result
        System.out.println("Division result: " + result);
        
    }
}

When the above code is executed, it produces the following result

Division using user defined method
Division result: 5.0

 

In the above program, the program defines a recursive function add(a,b).

  • if b=0; it simply returns a
  • Otherwise, it calls itself with (a+1) (b-1) until b become 0

The recursion gradually increases a and decreases b until the total sum is reached.

 

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Karmehavannan

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