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Java Leap Year Program|Java Program
In this article, we will discuss the concept of Java Leap Year Program.
In this Program, we are going to learn how to make sure the given year whether leap year or not using different methods in Java language.
This is done using if-else , if-else if-else, Nested -if,ternary operator and method in Java language.
Leap Year Program
Check whether the given year is leap or not- using if-else
In this program, we are going to learn how to make sure the given year whether leap year or not using if-else statements in Java language
Program 1
import java.util.Scanner;
public class Check_Leap_Year1{
public static void main(String args[]){
Scanner sc=new Scanner(System.in);
System.out.println("Please Enter year for check leap: ");
int year=sc.nextInt();
boolean is_Leap=false;
if ((year%400==0)||((year%4==0)&&(year%100!=0))){
System.out.println(year+" is a leap year ");
}
else{
System.out.println(year+" is not a leap year ");
}
}
}
When the above code is executed , it produces the following result
case 1
Please Enter year for check leap: 2000 2000 is a leap year
case 2
Please Enter year for check leap: 1994 1994 is not a leap year
Check whether the given year is leap or not- using if-else if
In this program, we are going to learn how to make sure the given year whether leap year or not using if-else if statements in Java language
Program 2
import java.util.Scanner;
public class Check_Leap_Year2{
public static void main(String args[]){
Scanner sc=new Scanner(System.in);
System.out.println("Please Enter year for check leap: ");
int year=sc.nextInt();
boolean is_Leap=false;
if(year%400==0){
System.out.println(year+" is a leap year ");
}
else if(year%100==0){
System.out.println(year+" is not a leap year ");
}
else if(year%4==0){
System.out.println(year+" is a leap year ");
}
else{
System.out.println(year+" is not a leap year ");
}
}
}
When the above code is executed , it produces the following result
case 1
Please Enter year for check leap: 2020 2020 is a leap year
case 2
Please Enter year for check leap: 2100 2100 is not a leap year
Check whether the given year is leap or not- using Nested if
In this program, we are going to learn how to make sure the given year whether leap year or not using Nested if statements in Java language
Program 3
import java.util.Scanner;
public class Check_Leap_Year{
public static void main(String args[]){
Scanner sc=new Scanner(System.in);
System.out.println("Please Enter year for check leap: ");
int year=sc.nextInt();
boolean is_Leap=false;
if(year%4==0){
if(year%100==0){
if(year%400==0){
is_Leap=true;
}else
is_Leap=false;
} else
is_Leap=true;
}else
is_Leap=false;
if(is_Leap==true)
System.out.println(year+" is a leap year ");
else
System.out.println(year+" is not a leap year ");
}
}
When the above code is executed , it produces the following result
case 1
Please Enter year for check leap: 2024 2024 is a leap year
case 2
Please Enter year for check leap: 2030 2030 is not a leap year
Check whether the given year is leap or not- using ternary operator
In this program, we are going to learn how to make sure the given year whether leap year or not using ternary operator in Java language
Program 4
import java.util.Scanner;
public class Check_Leap_Year3{
public static void main(String args[]){
Scanner sc=new Scanner(System.in);
System.out.println("Please Enter year for check leap: ");
int year=sc.nextInt();
String leap=(year%4==0 || year%100!=0 && year%400==0)?
"The entered year is a leap year":"This is not a leap year";
System.out.println(leap);
}
}
When the above code is executed , it produces the following result
Case 1
Please Enter year for check leap: 2024 The entered year is a leap year
Case 2
Please Enter year for check leap: 2030 This is not a leap year
Check whether the given year is leap or not- using method
In this program, we are going to learn how to make sure the given year whether leap year or not using user defined method in Java language
Program 5
import java.util.Scanner;
public class Check_Leap_YearMethod{
public static void main(String args[]){
Scanner sc=new Scanner(System.in);
System.out.println("Please Enter year for check leap: ");
int year=sc.nextInt();
findLeap(year);
}
static void findLeap(int year){
if(year!=0){
if(year%400==0){
System.out.println(year+" is a leap year ");
}
else if(year%100==0){
System.out.println(year+" is not a leap year ");
}
else if(year%4==0){
System.out.println(year+" is a leap year ");
}
else{
System.out.println(year+" is not a leap year ");
}
}
}
}
When the above code is executed , it produces the following result
Case 1
Please Enter year for check leap: 2024 2024 is a leap year
Case 2
Please Enter year for check leap: 2222 2222 is not a leap year
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