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In this article, we will discuss the concept of Code to count Positive, Negative numbers and zero in an array of C language
In this program, we are going to learn how to count the Positive numbers, Negative numbers and zeros in an array using several ways in C language.
This is done using for loop , while loop, do-while loop and function in C language
In this program, we will count positive numbers,negative numbers and zeros in an array using a for loop in C language
Program 1
#include <stdio.h> #include <stdlib.h> int main() { int i,size,countPos=0, countNeg=0, countZero=0,arr[100]; printf("Enter the array size\n"); scanf("%d",&size); printf("Enter %d elements\n",size); for(i=0; i<size; i++){ scanf("%d",&arr[i]); } for(i=0; i<size; i++){ if(arr[i]<0){ countNeg++; } else if(arr[i]>0){ countPos++; } else{ countZero++; } } printf("Positive numbers are %d\n",countPos); printf("Negative numbers are %d\n",countNeg); printf("zeros are %d",countZero); getch(); return 0; }
When the above code is executed it produces the following result
Enter the array size 10 enter 10 elements 45 0 -73 67 23 -87 -7 24 52 56 Positive numbers are 6 Negative numbers are 3 Zeros are 1
In this program, we will count positive numbers,negative numbers and zeros in an array using a while loop in C language
Program 2
#include <stdio.h> #include <stdlib.h> int main() { int i,size,countPos=0, countNeg=0, countZero=0,arr[100]; printf("Enter the array size\n"); scanf("%d",&size); printf("Enter %d elements\n",size); i=0; while( i<size){ scanf("%d",&arr[i]); i++; } i=0; while( i<size){ if(arr[i]<0){ countNeg++; } else if(arr[i]>0){ countPos++; } else{ countZero++; } i++; } printf("Positive numbers are %d\n",countPos); printf("Negative numbers are %d\n",countNeg); printf("zeros are %d",countZero); getch(); return 0; }
When the above code is executed it produces the following result
Enter the array size 12 Enter 10 elements 45 -67 0 64 -54 -34 45 23 62 72 68 -65 Positive numbers are 7 Negative numbers are 4 Zeros are 1
In this program, we will count positive numbers,negative numbers and zeros in an array using a do-while loop in C language
Program 3
#include <stdio.h> #include <stdlib.h> int main() { int i,size,countPos=0, countNeg=0, countZero=0,arr[100]; printf("Enter the array size\n"); scanf("%d",&size); printf("Enter %d elements\n",size); i=0; do{ scanf("%d",&arr[i]); i++; } while( i<size); i=0; do{ if(arr[i]<0){ countNeg++; } else if(arr[i]>0){ countPos++; } else{ countZero++; } i++; }while( i<size); printf("Positive numbers are %d\n",countPos); printf("Negative numbers are %d\n",countNeg); printf("zeros are %d",countZero); getch(); return 0; }
When the above code is executed it produces the following result
Enter the array size 8 Enter 8 elements 78 -98 0 45 67 83 29 Positive numbers are 5 Negative numbers are 2 Zeros are 1
In this program, we will count positive numbers,negative numbers and zeros in an array using a function in C language
Program 4
#include <stdio.h> #include <stdlib.h> int countPositive(int arr[],int size); int countNegative(int arr[],int size); int countZero(int arr[],int size); int main() { int size,i,arr[10]; int posCount=0,negCount=0,zeroCount=0; printf("Please enter the size of an array \n"); scanf("%d",&size); printf("Please enter the array elements \n"); for(i=0; i<size; i++){ scanf("%d",&arr[i]); } printf("Total positive numbers in this array= %d\n",countPositive(arr,size)); printf("Total Negative numbers in this array= %d\n",countNegative(arr,size)); printf("\nTotal zeros in this array= %d\n",countZero(arr,size)); getch(); return 0; } int countPositive(int arr[],int size){ int i, posCount=0; printf("\nList of positive number in this array: \n"); for(i=0; i<size; i++){ if(arr[i]>0){ printf("%d\n",arr[i]); posCount++; } } return posCount; } int countNegative(int arr[],int size){ int i, negCount=0; printf("\nList of negative number in this array: \n"); for(i=0; i<size; i++){ if(arr[i]<0){ printf("%d\n",arr[i]); negCount++; } } return negCount; } int countZero(int arr[],int size){ int i, zeroCount=0; for(i=0; i<size; i++){ if(arr[i]==0){ zeroCount++; } } return zeroCount; }
When the above code is executed it produces the following result
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