Odd Even

Code to Check whether the number is odd or even using operators in C++

Code to Check whether the number is odd or even using operators in C++

In this tutorial, we will discuss Program the Code to Check whether the number is odd or even using operators in C++

In this post, we are going to learn how to check whether the given number is odd or even using operator in C++ language

 

Program to Check whether the number is odd or even

Check whether the number is odd or even – using modular operator

Program 1

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;//variable declaration
    cout<<"Enter a integer to check odd or even\n";
//The program ask input from the user
    cin>>num;
//input value is stored in variable num

    if(num%2==0){//using modular operator
        cout<<num<<" is even";
    }
    else{cout<<num<<" is odd";}
    getch();
    return 0;
}

When the above code is executed ,it produces the following result

case 1

Enter a integer to check odd or even
9876
9876 is even

case 2

Enter a integer to check odd or even
8765
8765 is odd

 

Check whether the number is odd or even – using divisional operator

Program 2

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;//variable declaration
    cout<<"Enter a integer to check odd or even\n";
//The program ask input from the user
    cin>>num;
//input value is stored in variable num

    if((num/2)*2==num){//using divisional operator
        cout<<num<<" is even";
    }
    else{cout<<num<<" is odd";}
    getch();
    return 0;
}

When the above code is executed ,it produces the following result

case 1

Enter a integer to check odd or even
9874
9874 is even

case 2

Enter a integer to check odd or even
1357
1357 is odd

 

 

Check whether the number is odd or even – using bitwise operator

Program 3

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;//variable declaration
    cout<<"Enter a integer to check odd or even\n";
//The program ask input from the user
    cin>>num;
//input value is stored in variable num

    if((num & 1)==0){//using bit wise AND operator
        cout<<num<<" is even number";
    }
    else{cout<<num<<" is odd number";}
    getch();
    return 0;
}

When the above code is executed ,it produces the following result

case 1

Enter a integer to check odd or even
531
531 is odd number

case 2

Enter a integer to check odd or even
1388
1388 is even number

 

Check whether the number is odd or even – using ternary operator

Program 4

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;//variable declaration
    cout<<"Enter a integer to check odd or even\n";
//The program ask input from the user
    cin>>num;
//input value is stored in variable num

    (num%2==0)? cout<<num<<" is even":cout<<num<<" is odd"; //using ternary operator
    getch();
    return 0;
}

When the above code is executed ,it produces the following result

case 1

Enter a integer to check odd or even
975
975 is odd

case 2

Enter a integer to check odd or even
136
136 is even

 

Check whether the number is odd or even – using shift operator

Program 5

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;//variable declaration
    cout<<"Enter a number to check even or odd\n";
//The program ask input from the user
    cin>>num;
//input value is stored in variable num
    if((num>>1)<<1==num)  //using shift operator
        cout<<num<<" is Even number";
        else
         cout<<num<<" is Odd number";
         getch();
    return 0;
}

When the above code is executed ,it produces the following result

case 1

Enter a integer to check odd or even
57
57 is odd number

case 2

Enter a integer to check odd or even
46
46 is even number

 

Suggested for you

Data type in C++ language

Variable in C++ language

Operator in C++ language

While loop in C++ language

 

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Tags: C++ language

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