Divide two numbers in C++ language|6ways

Find division of two numbers

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Divide two numbers in C++ language|6ways

In this tutorial, we will discuss the Divide two numbers in C++ language

In this post, we are going to learn how to find division of two numbers using different 6 ways in C++ language

Divide two numbers in C++ -using standard method

Program 1

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num1=100,num2=20;
    int div=num1/num2;
    cout << "Division of "<<num1<<" and "<<num2<<" is: " << div<<endl;
    getch();
    return 0;
}

When the above program is executed, it produces the following result

Division of 100 and 20 is: 5

In this program,

Integer variable num1 and num2 both are declared and initialized
The num1 and num2 both are divided together and the value assigned to the integer variable div
Finally the program is displayed the output using cout<<.

Divide two numbers in C++ -using user input

Program 2

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num1,num2;
    cout<<"Enter two numbers: ";
    cin>>num1>>num2;
    int div=num1/num2;
    cout << "Division of "<<num1<<" and "<<num2<<" is: " << div<<endl;
    getch();
    return 0;
}

When the above program is executed, it produces the following result

Enter two numbers: 666
6
Division of 666 and 6 is: 111

in tis program,

Integer variable num1 and num2 both are declared,
The program takes input from the user
Then the user enters the input value for num1, num2
The program will read the input using cin>> and store the variables num1 and num2.
The num1 and num2 both are divided together and the value assigned to the integer variable div
Finally the program is displayed the output using cout<<

Divide two numbers in C++ -using function

Program 3

#include <iostream>
#include <conio.h>
using namespace std;

int division(int,int);   //function prototype / declaration
int main()
{
    int num1,num2,result;
    cout<<"Enter two number to find division\n";
    cin>>num1>>num2;  //numbers receive from the user
    result=division(num1,num2);//assign the output to variable result
    //function call
     cout << "Division of "<<num1<<" and "<<num2<<" is: " << result<<endl;
    getch();
    return 0;
}

int division(int a, int b)
{

        return a/b;
    }

When the above program is executed, it produces the following result

Enter two numbers:
560
70
Division of 560 and 70 is: 8

In this program

Declare a function named as division() with two int parameters
Declare num1,num2 and result.
The program takes input from the user
Then the user enters the input value for num1, num2
The program will read the input using cin>> and store the variables in num1, num2 respectively
Define the function (division())for find division
Call the function to produce output
Finally, the program displays the result of division using cout<<

Divide two numbers in C++ -using recursion

Program 4

#include <iostream>
#include <conio.h>
using namespace std;
int division(int,int);   //function prototype / declaration
int main()
{
    int num1,num2,result;
    cout<<"Enter two number to find division\n";
    cin>>num1>>num2;  //numbers receive from the user
    result=division(num1,num2);//assign the output to variable result
    //function call
     cout << "Division of "<<num1<<" and "<<num2<<" is: " << result<<endl;
    getch();
    return 0;
}


int division(int x, int y)
{
    if (y==0)
{
  return 0;
}
else if (x-y==0){
  return 1;
}
else if (x<y){
  return 0;
}
else{
  return (1+division(x-y,y));
}
}

When the above program is executed, it produces the following result

Enter two numbers to find division:
448
16
Division of 448 and 16 is: 28

Declare a function named as division() with two int parameters
Declare num1,num2 and result.
The program takes input from the user
Then the user enters the input value for num1, num2
The program will read the input using cin>> and store the variables in num1, num2 respectively
Define the function (division())for find division recursively
Call the recursive function to produce output
Finally, the program displays the result of subtraction using cout<<

Divide two numbers in C++ -using without divisional operator

Program 5

#include <iostream>
#include <conio.h>
using namespace std;


int division(int,int);   //function prototype / declaration
int main()
{
    int num1,num2,a,b,counter=0;
    cout<<"Enter two number to find division\n";
    cin>>a>>b;  //numbers receive from the user

   num1=a;
   num2=b;
   while(num1>=num2)
   {
       num1=num1-num2;
       counter++;
   }

     cout << "Division of "<<a<<" and "<<num2<<" is: " << counter<<endl;
    getch();
    return 0;
}

When the above program is executed, it produces the following result

Enter two numbers to find division:
1250
25
Division of 560 and 70 is:50

Divide two numbers in C++ -using pointer

Program 6

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num1,num2,*ptr1,*ptr2;
    //variable declaration

    cout << "Enter the first number: " << endl;
    cin>>num1;//read the value for num1
     cout << "Enter the second number: " << endl;
    cin>>num2;//read the value for num2

    ptr1=&num1;
    ptr2=&num2;

    int div = *ptr1/ *ptr2;//division calculation
      cout <<num1 <<" is devided by "<< num2<<" is: "<<div<<endl;
getch();
    return 0;
}

When the above program is executed, it produces the following result

Enter the first  number:
1250
Enter the second number
25
1250 is divided by 25 is: 50

Declare variables num1,num2 and div.
Declare pointer variables *ptr1, *ptr2.
The program takes input from the user
Then the user enters the input value for num1 and num2
The program will read the input using cin>> and store the variables in num1, num2 respectively
Address of the variables num1 and num2 assigned to pointer variables ptr1 and ptr2 respectively
calculate the division of the numbers using pointer variable and Assign the product value to div variable
Finally, the program displays the result using cout<<