Pyramid triangle number Pattern in C Language using for loop

Pyramid triangle number Pattern in C Language using for loop

In this tutorial, we will discuss the Pyramid triangle number Pattern in C Language using for loop

In the C Language, We can print various type of Pyramid shapes through nested for loop using number and special character

Pyramid triangle number Pattern

Pyramid number Pattern 1

Program 1

#include <stdio.h>
#include <stdlib.h>

int main()
{
int Noofrows;
printf("Enter number of rows to be printed!n");
scanf("%d",&Noofrows);

int row,colSpaces,colStar;
for(row=1; row<=Noofrows; row++)
{
for(colSpaces=Noofrows-row; colSpaces>=1; colSpaces--)
{
printf(" ");
}
for(colStar=1; colStar<=row; colStar++)
{
printf("%d ",row);
}
printf("n");
}
return 0;
}

When the above code is executed it produced the following result

Pyramid number Pattern 2

#include <stdio.h>
#include <stdlib.h>

int main()
{
int Noofrows;
printf("Enter number of rows to be printed!n");
scanf("%d",&Noofrows);

int row,colSpaces,colStar;
for(row=1; row<=Noofrows; row++)
{
for(colSpaces=Noofrows-row; colSpaces>=1; colSpaces--)
{
printf(" ");
}
for(colStar=1; colStar<=row; colStar++)
{
printf("%d ",colStar);
}
printf("n");
}
return 0;
}

Program 3

#include <stdio.h>
#include <stdlib.h>

int main()
{
int i,space,row,k,count,count1;
k=0;
count=0;
count1=0;

printf("Enter number of rowsn");
scanf("%d",&row);
for(i=1; i<=row; ++i)
{
for(space=1; space<=row-i; ++space){
printf(" ");
++count;
}
while(k != 2*i-1)
{
if(count<=row-1)

{
printf("%d",(i+k-2*count1));
}
else
{
++count1;
printf("%d",(i+k-2*count1));
}
++k;
}
count1=count=k=0;
printf("n");
}
return 0;
}

When the above code is executed it produced the following result

#include <stdio.h>
#include <stdlib.h>

int main()
{
int i, space, rows, m, count_x, count_y;
m=0; count_x=0; count_y=0;

printf("Enter number of rows: n");
scanf("%d",&rows);

for(i=1; i<=rows; ++i)
{
for(space=1; space <= rows-i; ++space)
{
printf("  ");
++count_x;
}

while(m != 2*i-1)
{
if (count_x <= rows-1)
{
printf("%d ", i+m);
++count_x;
}
else
{
++count_y;
printf("%d ", (i+m-2*count_y));
}
++m;
}
count_y = count_x = m= 0;

printf("n");
}
return 0;
}